Cosθ=√3/2 344112

Using The Pythagorean Trig Identity Video Khan Academy

Using The Pythagorean Trig Identity Video Khan Academy

2 II Complex numbers Magnitude, phase, real and imaginary parts A You're in EECS Now!The correct option is Aπ/3Givencos θ√3 sin θ=2 (i) This equation is of the form a cosθb sinθ=c, where a=1,b=√3 and c=2 Let a =r cos α,√3=r sinα ⇒r=√a2b2 =√13=√4=2 And, tan α= b a ⇒tanα= √3 1 ⇒tan α=√3 ⇒α = π 3 On putting a=1=r cos α and b=√3=r sin α in equation(i),we get r cosθ cosαr sinθ sin

Cosθ=√3/2

Cosθ=√3/2- Answer 1 From sin²θ cos²θ =1 and sinθ=2/3, we see that cosθ=√(1sin²θ) or cosθ=√5/3, where the sign of cosine is positive as it is in Quadrant IV x lies in 4th quadrant , cos x is ve , cos x = √5/3This question was previously asked in CDS Maths Previous Paper 2 (Held On )

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 Answer30°Stepbystep explanation√3sinθ cosθ = 0√3sinθ = cosθ √3 = cosθ / sinθ√3 = cotθ but we know that, cot30° = √3 ∴ cotθ = cot30°θ = 30° diyasheth1003 diyasheth1003 Math Secondary School answered • expert verifiedWe refer to a graph of the function tanθ as shown in Figure 1 tan⇒ cosθ = 1/2 and sinθ = √3/2 Since both the values of sinθ and cosθ are negative in III quadrant, Argument, θ = 2π/3 Thus, the modulus and argument of the complex number 1 i√3 are 2 and 2π/3 respectively NCERT Solutions Class 11 Maths Chapter 5 Exercise 52 Question 1

 (a) 3 – √5 / 2 (b) 3 √5 / 2 (c) 2 / 3 – √5 (d) 2 / 3 √5 1) a and d 2) d only 3) b only 4) None of these Solution (1) a and d tan (1 / 21 Find the real part, imaginary part, modulus, complex conjugate, and inverse of the following numbers (i) 2 34i, (ii) (34i) 2, (iii) 34i 3−4i, (iv) 1 √ i 1− √ 3i, and (v) cosθ isinθ To find the quantities we are looking for, we need to put the complex number into the form z = a bi Then, the modulus is z = √ Trigonometry Class 10 MCQ Questions with Answers Please see below Trigonometry Class 10 Mathematics MCQ Questions, solve the questions and compare your answers with the solutions provided below Question If tan A= 3/4 , then the value of sec A is 1v (a) 5/3

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